FCSS_NST_SE-7.6證照考試 & FCSS_NST_SE-7.6學習指南

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Fortinet FCSS_NST_SE-7.6 考試大綱：

主題簡介
主題 1
  • System troubleshooting: This section of the exam measures the skills of Network Security Support Engineers and addresses diagnosing and correcting issues within Security Fabric setups, automation stitches, resource utilization, general connectivity, and different operation modes in FortiGate HA clusters. Candidates work with built-in tools to effectively find and resolve faults.
主題 2
  • Security profiles: This part measures skills of Security Operations Specialists and covers identifying and resolving problems linked to FortiGuard services, web filtering configurations, and intrusion prevention systems to maintain protection across network environments.
主題 3
  • VPN: This section is aimed at IT Professionals and includes diagnosing and addressing issues with IPsec VPNs, specifically IKE version 1 and 2, to secure remote and site-to-site connections within the network infrastructure.
主題 4
  • Routing: This section focuses on Network Engineers and involves tackling issues related to packet routing using static routes, as well as OSPF and BGP protocols to support enterprise network traffic flow.
主題 5
  • Authentication: This section evaluates the abilities of System Administrators and requires troubleshooting both local and remote authentication methods, including resolving Fortinet Single Sign-On (FSSO) problems for secure network access.

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FCSS_NST_SE-7.6學習指南，FCSS_NST_SE-7.6真題

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最新的 Fortinet Certified Solution Specialist FCSS_NST_SE-7.6 免費考試真題 (Q74-Q79):

問題 #74
Refer to the exhibits.

FGT-1 is an area border router (ABR) that has interfaces in OSPF areas 0.0.0.0 and 0.0.0.5. FGT-3 acts as an autonomous system border router (ASBR), importing static routes into OSPF. FGT-2 is an internal router with all its interfaces belonging to area 0.0.0.5. FGT-1 is receiving all advertised routes from FGT-2, however, FGT-3 is not receiving any of the advertised routes from FGT-1. What is the most likely reason for this? (Choose one answer)

答案：A

解題說明：
The get router info ospf database brief output on FGT-2 clearly indicates that Area 0.0.0.5 is configured as a [Stub] area.
In OSPF, a Stub Area is specifically designed to reduce the size of the Link State Database (LSDB) on internal routers. The primary behavior of a Stub area is that it does not accept Type 5 (AS External) LSAs.
FGT-3 is the ASBR (Autonomous System Border Router) and is importing static routes, which are generated as Type 5 LSAs in the OSPF domain.
FGT-1 acts as the ABR (Area Border Router). Because Area 0.0.0.5 is a Stub area, FGT-1 blocks these Type 5 LSAs from entering Area 0.0.0.5.
Consequently, FGT-2 will not receive the specific external routes advertised by FGT-3. Instead, the ABR (FGT-1) injects a default route (0.0.0.0/0) into the Stub area to allow connectivity to the external world, which is visible in the database output.
While the question text mentions FGT-3 not receiving routes, the definitive configuration shown in the exhibit is the Stub area setting, which directly corresponds to the blocking of Type 5 LSA propagation (Option A).


問題 #75
Refer to the exhibit.

A network topology and a partial routing table are shown.
FortiGate has already been configured with a firewall policy that allows all ICMP traffic to flow from port1 to port3.
Which two changes can the administrator perform to ensure the server at 10.4.0.1/24 receives the ICMP echo reply from the laptop at 10.1.0.1/24? (Choose two.)

答案：A,C

解題說明：
The correct answers are A and C.
The study guide describes this exact asymmetric ICMP scenario. It states:
"The server sends an echo request to the PC through port2 of the local router, effectively bypassing FortiGate. When it receives the echo request, the PC responds with an echo reply through its default gateway, 10.1.0.2, which is port1 on FortiGate. Because there is no existing session, the echo reply is dropped. All subsequent echo replies are blocked." That means the current problem exists because:
the ICMP request bypasses FortiGate
the ICMP reply goes through FortiGate
FortiGate has no matching session, so it drops the reply
The study guide then shows the exact corrective option:
"Allowing asymmetric routing:"
config system settings
set asymroute enable
end
It further explains:
"After the packet passes through the FortiGate CPU, FortiGate forwards the packet using the FIB, even though there are no session matches. FortiGate forwards all subsequent echo replies using the FIB." So A is correct.
The other valid fix is to make the traffic symmetric by changing the laptop's default gateway so the reply no longer goes through FortiGate. In the exhibit, the alternate gateway is 10.1.0.254, which is the local router on the same subnet. If the laptop uses 10.1.0.254 instead of 10.1.0.2, the ICMP echo reply follows the same bypass path as the echo request, so the server receives it without involving FortiGate session validation. This makes C correct.
Why the other options are wrong:
B is wrong because this is not an RPF problem. The study guide explains RPF as a reverse path lookup used to validate whether a packet arrived on a legitimate interface, mainly for spoofing protection. The issue in this scenario is a missing session due to asymmetric routing, not a strict-versus-feasible RPF failure D is wrong because FortiGate already has the specific route 10.4.0.0/24 through port3 in the routing table shown in the exhibit, so adding a default static route to port3 is unnecessary and not the reason the echo reply is being dropped So the verified answers are: A, C.


問題 #76
Exhibit.

Refer to the exhibit, which shows two entries that were generated in the FSSO collector agent logs.
What three conclusions can you draw from these log entries? {Choose three.)

答案：A,C,E


問題 #77
Refer to the exhibit.

Partial output of the fssod daemon real-time debug command is shown. Which two conclusions can you draw from the output? (Choose two answers)

答案：A,E

解題說明：
The debug command diagnose debug application fssod -1 reveals the internal processing of the FortiGate Single Sign-On daemon.
* Option D (Agentless Polling): The output shows event_id=4768. Event ID 4768 (Kerberos TGT Request) is a Windows Event Log entry. The presence of specific Event IDs in the fssod debug, rather than a generic logon notification, indicates that the system is reading (polling) the Security Event Logs from the Domain Controller. This is characteristic of Agentless Polling Mode (or Collector Agent Polling Mode), where the FortiGate or Collector scrapes logs. In contrast, DC Agent mode intercepts logon calls directly and would typically provide more complete information, including the workstation name.
* Option A (Verification): Crucially, the output shows workstation=,, indicating the workstation name field is empty. In Polling Mode, certain Event IDs (like 4768) often do not contain the source workstation's hostname. Without the workstation name, the FortiGate (or Collector) cannot perform a workstation check (WMI/Registry poll) to verify if the user is still logged in. It essentially has to rely on the "dead entry timeout" because active verification is impossible without the target machine's name.
Option B is incorrect because DC Agents reliably capture workstation names. Option C is incorrect because the system cannot poll a workstation it cannot identify.


問題 #78
Refer to the exhibit, which shows the partial output of FortiOS kernel slabs.

Which statement is true?

答案：C

解題說明：
The study guide states:
"The kernel memory slabs are collections of objects with a common purpose. The kernel uses them to store information in memory." It also gives the exact calculation rule:
"Total slab size = available objects x object size"
From the exhibit:
tcp_session 3 5 1500 ...
So:
available objects = 5
object size = 1500
Therefore:
Total slab size = 5 × 1500 = 7500 kB
That makes D correct, and it is associated with the kernel, not user space.
Why the other options are wrong:
A is wrong because sctp_session 0 0 1600 ... gives 0 × 1600 = 0, but slabs are associated with the kernel, not user space.
B is wrong because ip_session 1 3 1200 ... gives 3 × 1200 = 3600, but again slabs are kernel memory, not user space.
C is wrong because ip6_session 0 0 1300 ... gives 0 × 1300 = 0, not 1300.


問題 #79
......

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